Corresponding angles
CongruentWhere: the same spot at each intersection (both upper-left, both lower-right, and so on).
Look for: an F shape. Pairs: ∠1 & ∠5, ∠2 & ∠6, ∠3 & ∠7, ∠4 & ∠8.
Geometry · Unit 2
Angle pairs made by parallel lines and a transversal, solving for x, two-column proofs, and the logic behind them. Learn it, then test yourself.
The big idea
When a transversal crosses two parallel lines, it makes eight angles. But there are only two different sizes: every acute angle is equal, every obtuse angle is equal, and one of each always adds up to 180°.
The arrow marks (›) on lines ℓ and m mean they are parallel. These rules only work when the lines are parallel, except vertical angles and linear pairs, which work for any two lines that cross.
With parallel lines, if two angles are both acute or both obtuse, they're equal. If one is acute and one is obtuse, they add to 180°. You still need the pair's name for proofs, but this tells you which equation to write.
Lines & angles
A transversal is a line that crosses two or more lines. Angles between the two lines are interior. Angles outside them are exterior. Each pair's name tells you where its two angles are.
Try it: pick a pair
Pick a pair above, or click any two angles in the drawing to see how they're related.
Where: the same spot at each intersection (both upper-left, both lower-right, and so on).
Look for: an F shape. Pairs: ∠1 & ∠5, ∠2 & ∠6, ∠3 & ∠7, ∠4 & ∠8.
Where: between the lines, on opposite sides of the transversal.
Look for: a Z shape. Pairs: ∠3 & ∠6, ∠4 & ∠5.
Where: outside the lines, on opposite sides of the transversal.
Pairs: ∠1 & ∠8, ∠2 & ∠7.
Where: across from each other at the same intersection. They make an X.
Pairs: ∠1 & ∠4, ∠2 & ∠3, ∠5 & ∠8, ∠6 & ∠7. True for any two crossing lines.
Where: between the lines, on the same side of the transversal. Also called consecutive interior angles.
Look for: a C or U shape. Pairs: ∠3 & ∠5, ∠4 & ∠6.
Where: outside the lines, on the same side of the transversal. Also called consecutive exterior angles.
Pairs: ∠1 & ∠7, ∠2 & ∠8.
Where: side by side at the same intersection, sharing a side. Together they make a straight line (180°).
Pairs: ∠1 & ∠2, ∠1 & ∠3, ∠2 & ∠4, and so on. True for any two crossing lines.
Top row: congruent. Bottom row: supplementary.
| Pair | Where the angles are | With parallel lines | Reason: lines ∥ → angles | Reason: angles → lines ∥ |
|---|---|---|---|---|
| Corresponding | Same spot at each intersection | Congruent | Corresponding Angles Postulate | Converse of the Corresponding Angles Postulate |
| Alternate interior | Between the lines, opposite sides | Congruent | Alternate Interior Angles Theorem | Converse of the Alternate Interior Angles Theorem |
| Alternate exterior | Outside the lines, opposite sides | Congruent | Alternate Exterior Angles Theorem | Converse of the Alternate Exterior Angles Theorem |
| Same-side interior | Between the lines, same side | Supplementary | Same-Side (Consecutive) Interior Angles Theorem | Converse of the Same-Side Interior Angles Theorem |
| Same-side exterior | Outside the lines, same side | Supplementary | Same-Side (Consecutive) Exterior Angles Theorem | Converse of the Same-Side Exterior Angles Theorem |
| Vertical | Across from each other, same intersection | Congruent (always) | Vertical Angles Theorem | Can't prove lines parallel |
| Linear pair | Side by side, same intersection | Supplementary (always) | Linear Pair Postulate | Can't prove lines parallel |
In the same plane and never meet. Written ℓ ∥ m.
Meet at a right angle (90°). Written a ⊥ b. The small square marks the right angle.
Cross at exactly one point, making two pairs of vertical angles.
Not in the same plane, and never meet. Like the two highlighted edges of a box.
If a line is perpendicular to one of two parallel lines, it is perpendicular to the other one too.
If a ∥ b and b ∥ c, then a ∥ c.
Algebra with angles
Most problems give two angles as expressions like (5x + 14)°. The angle pair tells you which equation to write.
Example 1 · congruent pair
Lines ℓ and m are parallel. Find x and the measure of each angle.
x = 13, and both angles are 56°
Example 2 · supplementary pair
Lines ℓ and m are parallel. Find x and both angles.
x = 27, and the angles are 120° and 60°
Example 3 · find a different angle
Lines ℓ and m are parallel. Find m∠1.
m∠1 = 110° (not 70°: always answer what was asked)
Example 4 · two crossing lines
Find x. (No parallel lines needed: vertical angles are always equal.)
x = 8 (each angle is 52°)
Example 5 · angle bisector
BD bisects ∠ABC. Find m∠ABC.
m∠ABC = 62°
Reasoning
A proof is a chain of statements, each backed by a reason. Start with the Given. End with what you need to Prove. Every step in between needs a definition, property, postulate, or theorem.
Lines ∥ → angles. Example: “ℓ ∥ m, so ∠3 ≅ ∠6” uses the Alternate Interior Angles Theorem.
Angles → lines ∥. Example: “∠3 ≅ ∠6, so ℓ ∥ m” uses the Converse of the Alternate Interior Angles Theorem.
These match the kinds of proofs in this unit. Try each step before you reveal it.
Proof 1 · proving lines are parallel
Givenp ∥ q, ∠1 ≅ ∠2
Prover ∥ s
| # | Statements | Reasons |
|---|---|---|
| 1 | p ∥ q | Given |
| 2 | ∠1 ≅ ∠3 | Corresponding Angles Postulate (∠1 and ∠3 are in the same spot where r crosses p and q) |
| 3 | ∠1 ≅ ∠2 | Given |
| 4 | ∠3 ≅ ∠2 | Transitive Property of Congruence (steps 2 and 3) |
| 5 | r ∥ s | Converse of the Alternate Interior Angles Theorem (∠3 and ∠2 are alternate interior angles along q) |
Why it works: the given parallel lines get you a congruent pair (step 2). Chain it to the given pair (step 4), and you have a congruent pair that proves the other two lines are parallel.
Proof 2 · three parallel lines
Givena ∥ b, b ∥ c
Prove∠1 ≅ ∠3
| # | Statements | Reasons |
|---|---|---|
| 1 | a ∥ b | Given |
| 2 | ∠1 ≅ ∠2 | Alternate Interior Angles Theorem (between a and b, opposite sides of t) |
| 3 | b ∥ c | Given |
| 4 | ∠2 ≅ ∠3 | Corresponding Angles Postulate (same spot where t crosses b and c) |
| 5 | ∠1 ≅ ∠3 | Transitive Property of Congruence (steps 2 and 4) |
Another way: a ∥ c by the Transitive Property of Parallel Lines. Then ∠1 and ∠3 are alternate interior angles for a and c, so ∠1 ≅ ∠3.
Proof 3 · parallel segments and a bisector
GivenDE ∥ KL; DE bisects ∠KDJ
Prove∠4 ≅ ∠5
| # | Statements | Reasons |
|---|---|---|
| 1 | DE ∥ KL | Given |
| 2 | DE bisects ∠KDJ | Given |
| 3 | ∠1 ≅ ∠2 | Definition of angle bisector |
| 4 | ∠1 ≅ ∠4 | Corresponding Angles Postulate (side JL is a transversal for DE and KL) |
| 5 | ∠2 ≅ ∠5 | Alternate Interior Angles Theorem (transversal DK) |
| 6 | ∠4 ≅ ∠5 | Transitive Property of Congruence (steps 3, 4, and 5) |
Why it works: the parallel segments connect ∠1 to ∠4 and ∠2 to ∠5, and the bisector connects ∠1 to ∠2. If a problem gives you the angle measures instead (like m∠4 = m∠5) and asks you to prove the bisector, use the same three connections in the other order, ending with “Definition of angle bisector.”
Some teachers want a separate line for “m∠1 = m∠2” (Definition of congruent angles) whenever you switch between ≅ and =. Ask what yours expects.
Reasoning
A conditional is an if-then statement. The “if” part is the hypothesis (p) and the “then” part is the conclusion (q).
If it is raining, then the ground is wet.
| Name | Symbols | How to make it | Example | Same truth as the original? |
|---|---|---|---|---|
| Conditional | p → q | The original | If it is raining, then the ground is wet. | It is the original |
| Converse | q → p | Switch the two parts | If the ground is wet, then it is raining. | Not always (a sprinkler could make it wet) |
| Inverse | ~p → ~q | Negate both parts | If it is not raining, then the ground is not wet. | Not always |
| Contrapositive | ~q → ~p | Switch and negate | If the ground is not wet, then it is not raining. | Always |
| Biconditional | p ↔ q | Join with “if and only if” | It is raining if and only if the ground is wet. | Only if the conditional and converse are both true |
“An angle is a right angle if and only if it measures 90°” is true: both “if right, then 90°” and “if 90°, then right” are true.
“Two angles are congruent if and only if they are vertical” is false: congruent angles don't have to be vertical.
To show a conditional is false, find a case where the hypothesis is true but the conclusion is false.
“If two angles are congruent, then they are vertical angles.” Counterexample: alternate interior angles with parallel lines are congruent, but not vertical.
If p → q is true and p is true, then q is true.
If a figure is a square, then it has four right angles.
ABCD is a square.
∴ ABCD has four right angles.
If p → q and q → r, then p → r.
If it snows, then school is canceled.
If school is canceled, then I sleep in.
∴ If it snows, then I sleep in.
If you study, then you pass.
Jordan passed.
∴ Jordan studied.
Invalid. Jordan could have passed another way. Knowing q doesn't tell you p.
If you study, then you pass.
Jordan didn't study.
∴ Jordan didn't pass.
Invalid. That's using the inverse, which isn't guaranteed.
If Sam practices, then he makes the team.
If Ava practices, then she makes the team.
∴ If Sam practices, then Ava makes the team.
Invalid. For syllogism, the conclusion of the first statement must be the hypothesis of the second.
Look at examples or a pattern and make a conjecture (an educated guess). It could be wrong: one counterexample disproves it.
Use facts, definitions, and the laws of logic to reach a conclusion that must be true. Proofs use deductive reasoning.
Glossary
Questions on angle pairs, solving for x, proofs, and logic. For solving questions, you type the number. The diagrams and numbers change every time you take it, and you see the answer and the steps after each question.
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Retakes use new numbers for the solving questions.